When people think of renewable energy, probably what comes
to mind is a mixture of solar panels, wave motion generators, geothermal
plants, hydroelectric dams and wind turbines. Of these, the two most associated
with the image of a sustainable society are probably solar panels and wind
turbines. That’s why when I caught a glimpse of this wind farm while at the
Jersey shore, I felt like I had been transported into some sort of futuristic
society apart from our own.
Fig. 1: Wind farm near Atlantic City (personal photo, hence the quality)
Assumedly, we all know that every energy-harvesting
method has efficiency limitations, even though some people like to pretend they
don’t. With solar panels, calculating efficiency can be complicated as it comes
down to a matter of quantum efficiency, but the efficiency limitations of wind
turbines, also called Betz’s Law, can be readily calculated with some physics.
Let’s explore this.
(Note: though not particularly difficult conceptually, this
derivation is math-heavy. I will do my best to explain the underlying logic as
we go along. Also, this explanation will be separated into three parts so that
your eyes don’t bleed from the endless stretch of math. Backbone calculations for Betz’s
Law come from the Wikipedia article and this MIT presentation, but I hope you
will find that my explanation, though lengthy, is more intuitive than these
sources. Enjoy!)
Let’s start with calculating how much power there exists in
a cylinder of wind with base area A corresponding to the arm span of the wind
turbine.
Fig. 2: Cylinder with base A and wind influx at velocity v (MIT)
Fig. 2: Cylinder with base A and wind influx at velocity v (MIT)
1. KE=1/2
mv2 (kinetic energy equation)
2. KE=W (work-energy equation)
3. P=d/dt(W)=1/2(dm/dt)v2+mv(dv/dt) (power equation, product rule)
2. KE=W (work-energy equation)
3. P=d/dt(W)=1/2(dm/dt)v2+mv(dv/dt) (power equation, product rule)
For equation two, let’s assume all work is converted to
electrical energy, not friction or blade deformation or other stuff. Now in
equation three, what normally happens is that the dm/dt term, or the change in
mass over time, is assumed to be zero, producing the familiar mv(dv/dt) or (d(mv)/dt)v
or Fv term associated with power. Instead, let’s assume that the air cylinder
has a constant known speed v1. Therefore, the term mv(dv/dt) goes to zero, and we are left
with equation 4:
4. P=1/2(dm/dt)v12
From fluid dynamics, we know that
5. dm/dt=(m/V)(dV/dt)=r(dV/dt)
or that the mass per volume, density, multiplied by the
change in volume over time is equal to the change in mass over time. Makes
sense, right? This is essentially just dimensional analysis. With constant wind
cylinder base A and changing length L, change in volume over time is defined as
6. dV/dt=d/dt(AL)=A(dL/dt)=Av1
Combining equations 4, 5 and 6, we get the general power
equation for a cylinder of wind to be
7. P=1/2rAv13
where r is density, A is cylinder base area (also area of
turbine span) and v is a constant wind velocity.
I’ll stop the first post here
since it’s a good spot to take a break. Read on to the next post to learn how to
calculate the effective wind speed acting on a wind turbine, and let me know in
the comments below if you have any questions.
No comments:
Post a Comment